4p^2-52pq-27q^2=0

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Solution for 4p^2-52pq-27q^2=0 equation:


Simplifying
4p2 + -52pq + -27q2 = 0

Reorder the terms:
-52pq + 4p2 + -27q2 = 0

Solving
-52pq + 4p2 + -27q2 = 0

Solving for variable 'p'.

Factor a trinomial.
(2p + -27q)(2p + q) = 0

Subproblem 1

Set the factor '(2p + -27q)' equal to zero and attempt to solve: Simplifying 2p + -27q = 0 Solving 2p + -27q = 0 Move all terms containing p to the left, all other terms to the right. Add '27q' to each side of the equation. 2p + -27q + 27q = 0 + 27q Combine like terms: -27q + 27q = 0 2p + 0 = 0 + 27q 2p = 0 + 27q Remove the zero: 2p = 27q Divide each side by '2'. p = 13.5q Simplifying p = 13.5q

Subproblem 2

Set the factor '(2p + q)' equal to zero and attempt to solve: Simplifying 2p + q = 0 Solving 2p + q = 0 Move all terms containing p to the left, all other terms to the right. Add '-1q' to each side of the equation. 2p + q + -1q = 0 + -1q Combine like terms: q + -1q = 0 2p + 0 = 0 + -1q 2p = 0 + -1q Remove the zero: 2p = -1q Divide each side by '2'. p = -0.5q Simplifying p = -0.5q

Solution

p = {13.5q, -0.5q}

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